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5y^2+14y-55=0
a = 5; b = 14; c = -55;
Δ = b2-4ac
Δ = 142-4·5·(-55)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-36}{2*5}=\frac{-50}{10} =-5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+36}{2*5}=\frac{22}{10} =2+1/5 $
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